x=5(x-5)(x+5)^2(x^2-49)

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Solution for x=5(x-5)(x+5)^2(x^2-49) equation: 



x=5(x-5)(x+5)^2(x^2-49)

We move all terms to the left:

x-(5(x-5)(x+5)^2(x^2-49))=0

We use the square of the difference formula

x^2+x+25=0

a = 1; b = 1; c = +25;
Δ = b2-4ac
Δ = 12-4·1·25
Δ = -99
Delta is less than zero, so there is no solution for the equation

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